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X^2-4.5X+2.8=0
a = 1; b = -4.5; c = +2.8;
Δ = b2-4ac
Δ = -4.52-4·1·2.8
Δ = 9.05
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{9.05}}{2*1}=\frac{4.5-\sqrt{9.05}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{9.05}}{2*1}=\frac{4.5+\sqrt{9.05}}{2} $
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